WebMar 1, 2024 · We can select top n per group with help of Subquery. Firstly, let's get top n Purchases per customer top_n_purchases_per_customer = Purchases.objects.filter ( customer=OuterRef ('customer') ).order_by ('-field_of_interest') [:10] Next, we can select Purchases with matching ids from the top 10 per each customer. WebMay 19, 2024 · yes, you can go ahead and test it. and print and check the queryset returned. I have a similar use case (considering the same model in the question), instead I had to fetch the latest record for each seller on each date. So I did this :- latest_sale = Sales.objects.order_by ("Saler", "-Date").distinct ("Saler") – Abhijeet Anand Shah.
django - how to get latest foreign key value in models.py - Stack Overflow
WebJan 25, 2024 · It's also easy to get an individual vendor / locale's current value with Costs.objects.filter(vendor_id=1, locale_id=10).latest(). What I'm interested in getting is all of the latest cost values for each vendor / locale combo. So essentially running the latest() function over each combination and getting a list / queryset as a result. WebJan 24, 2024 · To signify this, in Django positional arguments to .distinct () can be passed only in Postgresql ). In Django we can do this with QuerySet like this: Portfolio.objects.order_by ().order_by ( 'code', # first, cause we want to group by this value '-created' # descending order, latest / max will be first ).distinct ('code') projection income
Django selecting top n records per group using ORM
WebDec 16, 2024 · Get top n records for each group with Django queryset Ask Question Asked 2 years, 3 months ago Modified 2 years, 3 months ago Viewed 1k times 1 I have a model like the following Table, create table `mytable` ( `person` varchar (10), `groupname` int, `age` int ); And I want to get the 2 oldest people from each group. WebDec 11, 2024 · 1 Answer Sorted by: 0 The dataset you need can be efficiently built with prefetch_related. userinfo = UserInfo.objects.all ().prefetch_related ("attendancerecord_set") for ui in userinfo: for ar in ui.addendancerecord_set.all (): print (ar) in template code Webfrom django.db.models import Q group_dict = Model.objects.values ('business_id').annotate (max_date=Max ('date')).order_by () params = Q () for obj in group_dict: params = (Q (business_id__exact=obj ['business_id']) & Q (date=obj ['max_date'])) qs = Model.objects.filter (params) This link can help u. lab results for mono