WebSolution The correct option is A 4 sin A sin B sin C Find the value of s i n 2 A + s i n 2 B + s i n 2 C: Given data: A + B + C = π ⇒ 2 A + 2 B + 2 C = 2 π Web相关热门 . 在高中数学题目中acosA=bcosB 这个条件可以推出什么东西? 答：那么acosA=bcosB 可以转化为 sinAcosA=sinBcosB 1/2sin2A=1/2sin2B 所以sin2A=sin2B 所以2A=2B 或者2A=π-2B 所以A=B 或者A+B=π/2 所以是等腰三角形或者直角三角形 ... acosa=bcosb是什么三角形 答：acosA=bcosB → a=bcosB/cosA-① 因为是三角形中,所 …

In any triangle ABC, prove that sin2A + sin2B – sin2C

WebPROVE SIN2A+SIN2B-SINC=4COSACOSBSINC Dear bayana, he double angle formula: sin 2Θ = 2 sin Θ cos Θ sin 2A + sin 2B - sin 2C ... = 2 sin A cos ... its sin2a+sin2b-sin2c=4 cosa cosb sinc. applying SIN2X=2SINXCOSX. A+B+C=180. AND A IS SUPPLEMENT ANGLE OF (B+C) ... The sides of a right angle triangle PQR are PQ=7cm; QR=25cm and angle P=90 … Websin2A + sin2B + sin2C = 4cosAcosBcosC Solution : sin2A + sin2B + sin2C : = 2sin (A + B)cos (A - B) + sin2C = 2sin (90 - C)cos (A - B) + 2sinCcosC = 2cosCcos (A - B) + 2sinCcosC = … diana\u0027s nursery valley center

trigonometry - Prove $\sin^2(A)+\sin^2(B) …

Web正弦定理与余弦定理及应用练习题-(B)①若sin2A=sin2B,则 ABC是等腰三角形②sinA=cosB，则 ABC是直角三角形③若sin2A+sin2B+sin2C＜2,则 ABC是钝角三角形④若cos(A-B)cos(B-C)cos(C-A)=1,则 ABC是 WebIn ΔABC, if sin2A + sin2B + sin2C = 2, then the triangle isIn triangle ABC, if sin^2A+sin^2B=sin^2C, then the triangle isin a Δ ABC , if sin^2 A + sin^2 B + ... In ΔABC, if sin2A + sin2B +... Web⇒(a−b) 2+(b−c) 2+(a−c) 2=0 Since, all the three terms in the above addition are positive which cannot be summed up to zero. Therefore, (a−b)=(b−c)=(c−a)=0 ⇒a=b=c Thus, A=B=C=60 o=sin 2A+sin 2B+sin 2C=3× 43= 49 Video Explanation Solve any question of Determinants with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions cit bank div of